kc3-lang/kc3/.ic3_history

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• Hash : f580ef43
  Author : Thomas de Grivel
  Date : 2024-03-24T11:10:46
  

  add missing eval

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• .ic3_history

•   1 + 1
    2 + 2
  end
  def
  123 = 123
  def
  def a = 1
  def 1 = 1
  def a = 1
  def 1 = 1
  def a = 1
  a
  def a = 1
  a
  def a = fn (x) do x * 2 end
  a
  List.reverse
  license
  def reverse = fn (x) { List.reverse(x) }
  reverse([1, 2, 3])
  def reverse = fn (x) { [:reversed | List.reverse(x)] }
  reverse([1, 2, 3])
  def reverse = fn (x) { List.reverse(x) }
  reverse([1, 2, 3])
  def reverse = fn (x) { [:reversed | List.reverse(x)] }
  reverse([1, 2, 3])
  def reverse = fn (x) { List.reverse(x) }
  reverse([1, 2, 3])
  def reverse = fn (x) { List.reverse(x) }
  C3.reverse
  def dt = macro (x) do
    quote do
      x = ^ x
      {x, x}
    end
  end
  dt(200)
  def dt = macro (x) do
    quote do
      x = unquote x
  def dt = macro (x) do
    quote do
      x = unquote(x)
      {x, x}
    end
  end
  dt(200)
  dt(a)
  a = [1, 2, 3]
  dt(a)
  def dt = macro (x) do
    quote do
      x = ^ unquote(x)
      {x, x}
    end
  end
  dt(a)
  1 + 10000000000000000000000000000000000000000000
  def beaucoup = 1 + 10000000000000000000000000000000000000000000
  type(beaucoup)
  def beaucoup = 1 + 10000000000000000000000000000000000000000000
  type(beaucoup)
  beaucoup
  def beaucoup = (U8) beaucoup
  type(beaucoup)
  beacoup
  beaucoup
  1 / 4
  (Ratio) 1 / 4
  (Ratio) 1 / 4 * 2
  1/4 * 2
  type(1/4)
  1/4 / 13/12
  1/4 / 13/12 * 2
  (Complex) 1
  1 +i 2
  type(1 +i 2)
  1 +i 2 +i 3
  (1 +i 2) * (2 +i 3)
  sqrt(-1)
  sqrt(-1) * sqrt(-1)
  sqrt(-2) * sqrt(-2)
  def dt = macro (x) do
    quote do
      x = ^ unquote(x)
      {x, x}
    end
  end
  dt(200)
  dt(200 * 200)
  dt(sqrt(-1))
  def double = fn (x) { x * 2 }
  double(200)
  double(beaucoup)
  def beaucoup = 1 + 10000000000000000000000000000000000000000000
  double(beaucoup)
  dt
  double(3/4)
  1 / double(3/4)
  

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