Commit 79d1509cb06ba9067f56e2c62394d7bc60fa6bf2
2017-10-10T11:39:45
x86: align alloca to 16-byte boundary Align the stack allocation to a 16-byte boundary. This ensures that the stack parameters are 16-byte aligned which is needed for some instructions.
diff --git a/src/x86/ffi.c b/src/x86/ffi.c
index 3b4e25e..897498f 100644
--- a/src/x86/ffi.c
+++ b/src/x86/ffi.c
@@ -32,6 +32,7 @@
#ifndef __x86_64__
#include <ffi.h>
#include <ffi_common.h>
+#include <stdint.h>
#include <stdlib.h>
#include "internal.h"
@@ -674,7 +675,8 @@ ffi_raw_call(ffi_cif *cif, void (*fn)(void), void *rvalue, ffi_raw *avalue)
}
bytes = cif->bytes;
- argp = stack = alloca(bytes + sizeof(*frame) + rsize);
+ argp = stack =
+ (void *)((uintptr_t)alloca(bytes + sizeof(*frame) + rsize + 15) & ~16);
frame = (struct call_frame *)(stack + bytes);
if (rsize)
rvalue = frame + 1;